Step-by-Step Lesson • Step 1 of 6

ARCH-C-02: Diatomic Mass Spectrometry (m/z Peak Ratios 9:6:1 & 1:2:1) & Molecular Ion Combinations

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-C-02: Why the 140s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~140s (Blows 90s Clock)
Each bromine atom in Br2+\text{Br}_2^+ has probability 0.50.5 of being 79Br^{79}\text{Br} and 0.50.5 of being 81Br^{81}\text{Br}. A molecular mass of 160160 arises from either 79Br−81Br^{79}\text{Br}-^{81}\text{Br} (0.5×0.5=0.250.5 \times 0.5 = 0.25) or 81Br−79Br^{81}\text{Br}-^{79}\text{Br} (0.5×0.5=0.250.5 \times 0.5 = 0.25). Summing both arrangements gives 0.25+0.25=0.50=50%0.25 + 0.25 = 0.50 = 50\% (~110s).
The Fast ShortcutTarget: 35s (Saves 105s)
Line 1 (Binomial Ratio): (1:1)2  ⟹  1:2:1(1:1)^2 \implies 1 : 2 : 1 peak heights at m/z=158,160,162m/z = 158, 160, 162.
Line 2 (Middle Share): 21+2+1×100%=50%\frac{2}{1 + 2 + 1} \times 100\% = 50\% (25s).
Where Students Lose Time: In 5 past UAT-UK questions (2.22% of Chemistry), candidates lose 105s by forgetting that heteronuclear diatomic ions (⁷⁹br⁸¹br)+ and (⁸¹br⁷⁹br)+ can form in 2 ordered ways (2pq). Instead, apply C17 with Maths 1 skill M7.7.
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