Step-by-Step Lesson • Step 1 of 6

ARCH-C-05: Oxidation State Assignment, Redox Disproportionation & Ionic Half-Equation Balancing

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-C-05: Why the 130s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~130s (Blows 90s Clock)
Evaluate each statement: (1) In elemental Cl2\text{Cl}_2, Cl\text{Cl} has oxidation state 00; in NaCl\text{NaCl} it is −1-1; in NaClO\text{NaClO}, (+1)+x+(−2)=0  ⟹  x=+1(+1) + x + (-2) = 0 \implies x = +1 (Statement 1 is correct). (2) Because chlorine is simultaneously oxidised (0→+10 \rightarrow +1) and reduced (0→−10 \rightarrow -1), it undergoes disproportionation (Statement 2 is correct). (3) Oxygen has oxidation state −2-2 in all species here; only in peroxides (O22−\text{O}_2^{2-}) is it −1-1 (Statement 3 is incorrect) (~120s).
The Fast ShortcutTarget: 35s (Saves 95s)
Line 1 (Kill Statement 3): Oxygen is −2-2 in NaClO\text{NaClO} (not a peroxide)   ⟹  \implies Statement 3 False.
Line 2 (Verify 1 & 2): Cl:0→−1\text{Cl}: 0 \rightarrow -1 and +1+1 (disproportionation)   ⟹  \implies 1 and 2 only (25s).
Where Students Lose Time: In 13 past UAT-UK questions (5.78% of Chemistry), candidates lose 95s by confusing 'is oxidised' (loses electrons = reducing agent) with 'oxidising agent' (gains electrons = is reduced). Instead, apply C5 with Maths 1 skill M4.2.
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