Step-by-Step Lesson • Step 1 of 6

ARCH-C-06: Chemical Bonding, Giant vs. Simple Lattice Property Tables & Allotropes (Graphite/Diamond)

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-C-06: Why the 125s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~125s (Blows 90s Clock)
Classify each substance by its melting point and electrical conductivity: (1) X\text{X} has a high melting point (801 ∘C801\,^\circ\text{C}) and conducts only when molten or aqueous (where ions become mobile), which is the signature of a giant ionic lattice (such as NaCl\text{NaCl}). (2) Y\text{Y} has a very high melting point (1710 ∘C1710\,^\circ\text{C}) and never conducts, which is a giant covalent structure (such as SiO2\text{SiO}_2). (3) Z\text{Z} sublimes at −78 ∘C-78\,^\circ\text{C} and never conducts, as only weak intermolecular forces are overcome, so Z\text{Z} is a simple molecular structure (~110s).
The Fast ShortcutTarget: 30s (Saves 95s)
**Line 1 (Conductivity Key for X\text{X}):** Insulator(s) + Conductor(l/aq)   ⟹  X=\implies \text{X} = Giant ionic lattice.
**Line 2 (Melting Point Split for Y,Z\text{Y}, \text{Z}):** 1710 ∘C  ⟹  Y=1710\,^\circ\text{C} \implies \text{Y} = Giant covalent; −78 ∘C  ⟹  Z=-78\,^\circ\text{C} \implies \text{Z} = Simple molecular (20s).
Where Students Lose Time: In 9 past UAT-UK questions (4% of Chemistry), candidates lose 95s by classic trap: boiling simple molecules overcomes weak intermolecular forces only; covalent bonds remain intact. Instead, apply C6 with Maths 1 skill M3.4.
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