Step-by-Step Lesson • Step 1 of 6

ARCH-C-15: Periodic Table Trends (Groups 1, 17, 18), Metal Reactivity Displacement & Extraction Series

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-C-15: Why the 125s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~125s (Blows 90s Clock)
Evaluate each statement: Statement 1 is correct (Group 1 metals lose 11 electron; larger atomic radius and increased inner-shell shielding make electron loss easier down the group). Statement 2 is correct (Group 17 halogens gain 11 electron; larger radius and increased shielding weaken attraction for an incoming electron down the group). Statement 3 is correct (metallic bonding weakens down Group 1, so mp/bp\text{mp/bp} decrease). Statement 4 is false (intermolecular forces between X2\text{X}_2 molecules strengthen down Group 17 as molecular size increases, so mp/bp\text{mp/bp} increase from F2(g)\text{F}_2\text{(g)} to I2(s)\text{I}_2\text{(s)}). Thus 1, 2 and 3 only are correct (~95s).
The Fast ShortcutTarget: 30s (Saves 95s)
Line 1 (Reactivity Opposite): Group 1 loses e−e^- (reactivity ↑\uparrow); Group 17 gains e−e^- (reactivity ↓\downarrow)   ⟹  \implies 1 & 2 True.
**Line 2 (mp/bp\text{mp/bp} Opposite):** Group 1 mp/bp\text{mp/bp} ↓\downarrow (3 True); Group 17 mp/bp\text{mp/bp} ↑\uparrow (Cl2(g)→Br2(l)→I2(s)\text{Cl}_2\text{(g)} \rightarrow \text{Br}_2\text{(l)} \rightarrow \text{I}_2\text{(s)}, 4 False) (20s).
Where Students Lose Time: In 9 past UAT-UK questions (4% of Chemistry), candidates lose 95s by down group 1: reactivity increases (easier to lose outer e^-) and mp decreases. down group 17: reactivity decreases (harder to gain outer e^-) and mp/bp increases (stronger intermolecular forces). Instead, apply C14 with Maths 1 skill M3.4.
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