Step-by-Step Lesson • Step 1 of 6

ARCH-P-02: Electrical Power Dissipation (P = IV = I^2R = V^2/R), Grid Efficiency & Energy (E = VIt)

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-P-02: Why the 140s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~140s (Blows 90s Clock)
First compute total energy input Ein=Pt=200×(5×60)=60000 JE_{\text{in}} = P t = 200 \times (5 \times 60) = 60000\text{ J}. Next compute useful output Euseful=15%×60000=9000 JE_{\text{useful}} = 15\% \times 60000 = 9000\text{ J}. Subtracting gives Ewasted=60000−9000=51000 JE_{\text{wasted}} = 60000 - 9000 = 51000\text{ J} (~120s).
The Fast ShortcutTarget: 40s (Saves 100s)
Line 1 (Wasted Power): Pwaste=(1−0.15)×200=170 WP_{\text{waste}} = (1 - 0.15) \times 200 = 170\text{ W}.
**Line 2 (Multiply by 60t60t):** Ewaste=170×(5×60)=51000 JE_{\text{waste}} = 170 \times (5\times 60) = 51000\text{ J} (25s).
Where Students Lose Time: In 11 past UAT-UK questions (4.72% of Physics), candidates lose 100s by substituting supply terminal voltage v_supply instead of cable voltage drop δv into v²/r. Instead, apply P1 with Maths 1 skill M1.2.
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