ARCH-P-10: Specific Heat Capacity (Q = mcΔT), Latent Heat (Q = mL) & Electrical Heating Curves (Pt = mcΔT)

Full 15-Q Timed Drill

Step 1 of 6 • The Core Idea

ARCH-P-10: Why the 140s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~140s (Blows 90s Clock)

Total energy supplied is

E_{\text{in}} = P t = 40 \times 50 = 2000\text{ J}

. Convert mass

m = \frac{5}{1000}\text{ kg}

and compute energy retained by the tip:

Q = mc\Delta T = 0.005 \times 400 \times 200 = 400\text{ J}

. Energy lost to surroundings is

2000 - 400 = 1600\text{ J}

(~120s).

The Fast ShortcutTarget: 40s (Saves 100s)

**Line 1 (Unit Guardrail

\text{g} \to \text{kg}

):**

Q_{\text{tip}} = \frac{5}{1000} \times 400 \times 200 = 400\text{ J}

.
**Line 2 (Subtract from

Pt

):**

E_{\text{lost}} = (40\times 50) - 400 = 2000 - 400 = 1600\text{ J}

(25s).

Where Students Lose Time: In 11 past UAT-UK questions (4.72% of Physics), candidates lose 100s by failing to divide mass in grams by 1000 to match kg. Instead, apply P4 with Maths 1 skill M1.2.

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