Step-by-Step Lesson • Step 1 of 6

ARCH-P-14: Hydrostatic Fluid Pressure (P = ρgh), Archimedes Upthrust, Composite Density & Ideal Gas Pistons (P_1V_1 = P_2V_2)

Full 15-Q Timed Drill
Step 1 of 6 • The Core Idea

ARCH-P-14: Why the 145s Classroom Method Fails Under the 90s Clock

Standard Classroom Method (Too Slow)~145s (Blows 90s Clock)
Mass of block is m=Wg=3010=3 kg=3000 gm = \frac{W}{g} = \frac{30}{10} = 3\text{ kg} = 3000\text{ g}. Net volume of solid material is Vnet=103−(52×10)=1000−250=750 cm3V_{\text{net}} = 10^3 - (5^2 \times 10) = 1000 - 250 = 750\text{ cm}^3. Thus ρ=mVnet=3000750=4.00 g cm−3\rho = \frac{m}{V_{\text{net}}} = \frac{3000}{750} = 4.00\text{ g cm}^{-3} (~120s).
The Fast ShortcutTarget: 40s (Saves 105s)
Line 1 (Net Material Volume): Vnet=10(102−52)=750 cm3V_{\text{net}} = 10(10^2 - 5^2) = 750\text{ cm}^3; mass m=3000 gm = 3000\text{ g}.
Line 2 (Divide): ρ=3000750=4.00 g cm−3\rho = \frac{3000}{750} = 4.00\text{ g cm}^{-3} (25s).
Where Students Lose Time: In 14 past UAT-UK questions (6.01% of Physics), candidates lose 105s by boyle's law p₁*v₁ = p₂*v₂ requires total absolute pressure (atmospheric + piston pressure), never gauge pressure alone. Instead, apply P5 with Maths 1 skill M1.2.
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