UAT-UK SPEC CODE: C4 (Quantitative chemistry)ASSUMED MATHS 1 PREREQUISITE: M1.2FREQUENCY: VERY HIGH

Molar Gas Volume (24 dm^3 at rtp), Ideal Gas Scaling, Percentage Yield & Atom Economy

Deconstructed from 18 past UAT-UK questions (8% of all historical Chemistry papers). Students using standard A-Level classroom methods spend an average of 150s on this archetype—blowing past the 90s ESAT budget. Using the 2-line Sub-90 heuristic below compresses solve time to 40s (saving 110s per question).

Historical Frequency
18 Past Qs
8% of Chemistry
Classroom Trap Time
150s
+60s over 90s budget
Sub-90 Target Time
40s
Banks +110s on the clock
Dominant UI Format
5-Option A–E
Maths 1 Skill: M1.2

Card 1 & Card 2 Preview: The Classroom Time Trap vs. Sub-90 2-Line Rule

Excerpted from our interactive 6-Step Topic Lesson for ARCH-C-04.

Launch All 6 Active-Recall Cards
CARD 1 OF 6 • THE CLASSROOM TIME TRAP (150s)
Why Students Bleed Time:
First calculate the moles of magnesium: n(Mg)=0.6024=0.025 moln(\text{Mg}) = \frac{0.60}{24} = 0.025\text{ mol}. From the 1:11:1 stoichiometry, n(H2)=0.025 moln(\text{H}_2) = 0.025\text{ mol}. At rtp, V(H2)=0.025×24 dm3=0.60 dm3=600 cm3V(\text{H}_2) = 0.025 \times 24\text{ dm}^3 = 0.60\text{ dm}^3 = 600\text{ cm}^3 (~105s).
In 18 past UAT-UK questions (8% of Chemistry), candidates lose 110s by mixing cm³ and dm³ without applying 1 dm³ = 1000 cm³. Instead, apply C4 with Maths 1 skill M1.2.
CARD 2 OF 6 • THE 2-LINE SUB-90 HEURISTIC (<40s)
**Line 1 (2424 Cancellation):** V(cm3)=mAr×24,000=0.6024×24,000V(\text{cm}^3) = \frac{m}{A_r} \times 24,000 = \frac{0.60}{24} \times 24,000.
**Line 2 (Cancel 2424):** 0.60×1000=600 cm30.60 \times 1000 = 600\text{ cm}^3 (20s).
Sanity & Limit Check: Verify units/signs against unit_or_prefix_mismatch (Dividing cm³ by 24 instead of 24,000 when converting gas volume at rtp to moles) and factor_of_two_or_stoichiometry_trap (Using atomic mass instead of diatomic M_r (e.g. 14 instead of 28 for N₂, or 35.5 instead of 71 for Cl_2) when converting gas volume to mass).

Examiner Distractor Blueprint for ARCH-C-04

FOIL #1unit_or_prefix_mismatch
Dividing cm³ by 24 instead of 24,000 when converting gas volume at rtp to moles

Mixing cm³ and dm³ without applying 1 dm³ = 1000 cm³.

Open Unit / Prefix Mismatch Clinic
FOIL #2factor_of_two_or_stoichiometry_trap
Using atomic mass instead of diatomic M_r (e.g. 14 instead of 28 for N₂, or 35.5 instead of 71 for Cl_2) when converting gas volume to mass

Forgetting that common elemental gases (H2, N2, O2, F2, Cl2) are diatomic.

Open Factor-of-2 / Stoichiometry Clinic
FOIL #3subsystem_isolation_trap
Swapping percentage yield (actual / theoretical * 100%) with atom economy (M_r of desired product / sum of M_r of all products * 100%)

Confusing experimental reaction efficiency (% yield) with stoichiometric formula utilization (atom economy).

Open Subsystem Isolation Trap Clinic
FOIL #4intermediate_stop_trap
Calculating theoretical 100% gas volume without multiplying by the given percentage yield fraction

Stopping at theoretical stoichiometric yield before scaling by actual % yield.

Open Intermediate Stop Trap Clinic

Try 1 Live Sample Question Under the 90-Second Stopwatch

Press W to open the 2-line dry-wipe scratchpad, select A–E, and lock in to reveal the Dual-View solution.

sub90 ESAT Stopwatch Emblemsub90 ESAT
ARCH-C-04: Molar Gas Volume (24 dm^3 at rtp), Ideal Gas Scaling, Percentage Yield & Atom Economy (Sample)Chemistry
00:00.0
SUB-90 ZONE (<40S)
0.0s40s Sub-9090s ESAT Budget150s Classroom
Question 1 of 1ARCH-C-04 (6-Card Lesson)Format: Standard 5-Option
Right-click any option to cross out • Keys A–E + Enter
Question 1 of 1 • 90s Target

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The question stem, diagram, and answer options are hidden behind this pre-start gate. When you click below, the question will reveal and your 90-second split stopwatch will immediately begin ticking.

Chemistry•ARCH-C-04•Standard 5-Option
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