UAT-UK SPEC CODE: C5 (Oxidation, reduction and redox)ASSUMED MATHS 1 PREREQUISITE: M4.2FREQUENCY: HIGH

Oxidation State Assignment, Redox Disproportionation & Ionic Half-Equation Balancing

Deconstructed from 13 past UAT-UK questions (5.78% of all historical Chemistry papers). Students using standard A-Level classroom methods spend an average of 130s on this archetype—blowing past the 90s ESAT budget. Using the 2-line Sub-90 heuristic below compresses solve time to 35s (saving 95s per question).

Historical Frequency
13 Past Qs
5.78% of Chemistry
Classroom Trap Time
130s
+40s over 90s budget
Sub-90 Target Time
35s
Banks +95s on the clock
Dominant UI Format
1-2-3 Statement
Maths 1 Skill: M4.2

Card 1 & Card 2 Preview: The Classroom Time Trap vs. Sub-90 2-Line Rule

Excerpted from our interactive 6-Step Topic Lesson for ARCH-C-05.

Launch All 6 Active-Recall Cards
CARD 1 OF 6 • THE CLASSROOM TIME TRAP (130s)
Why Students Bleed Time:
Evaluate each statement: (1) In elemental Cl2\text{Cl}_2, Cl\text{Cl} has oxidation state 00; in NaCl\text{NaCl} it is −1-1; in NaClO\text{NaClO}, (+1)+x+(−2)=0  ⟹  x=+1(+1) + x + (-2) = 0 \implies x = +1 (Statement 1 is correct). (2) Because chlorine is simultaneously oxidised (0→+10 \rightarrow +1) and reduced (0→−10 \rightarrow -1), it undergoes disproportionation (Statement 2 is correct). (3) Oxygen has oxidation state −2-2 in all species here; only in peroxides (O22−\text{O}_2^{2-}) is it −1-1 (Statement 3 is incorrect) (~120s).
In 13 past UAT-UK questions (5.78% of Chemistry), candidates lose 95s by confusing 'is oxidised' (loses electrons = reducing agent) with 'oxidising agent' (gains electrons = is reduced). Instead, apply C5 with Maths 1 skill M4.2.
CARD 2 OF 6 • THE 2-LINE SUB-90 HEURISTIC (<35s)
Line 1 (Kill Statement 3): Oxygen is −2-2 in NaClO\text{NaClO} (not a peroxide)   ⟹  \implies Statement 3 False.
Line 2 (Verify 1 & 2): Cl:0→−1\text{Cl}: 0 \rightarrow -1 and +1+1 (disproportionation)   ⟹  \implies 1 and 2 only (25s).
Sanity & Limit Check: Verify units/signs against sign_or_direction_flip (Identifying the species that is oxidised as the oxidising agent (instead of the reducing agent)) and factor_of_two_or_stoichiometry_trap (Forgetting to divide by subscript 2 in Cr_2O_7²- (giving +12 instead of +6 for Cr) or S_2O_3²-).

Examiner Distractor Blueprint for ARCH-C-05

FOIL #1sign_or_direction_flip
Identifying the species that is oxidised as the oxidising agent (instead of the reducing agent)

Confusing 'is oxidised' (loses electrons = reducing agent) with 'oxidising agent' (gains electrons = is reduced).

Open Sign / Direction Flip Clinic
FOIL #2factor_of_two_or_stoichiometry_trap
Forgetting to divide by subscript 2 in Cr_2O_7²- (giving +12 instead of +6 for Cr) or S_2O_3²-

Computing total oxidation state of 2 atoms without dividing by 2.

Open Factor-of-2 / Stoichiometry Clinic
FOIL #3multi_statement_linchpin_foil
Classifying a reaction where two different reactants form one product (comproportionation) or normal redox as disproportionation

Disproportionation requires ONE element in a SINGLE reactant species to be simultaneously oxidised and reduced (e.g. Cl_2 -> Cl^- + ClO_3^-).

Open Multi-Statement Linchpin Foil Clinic
FOIL #4fence_post_or_domain_trap
Assigning oxygen as -2 in H_2O_2 (peroxide, -1) or OF_2 (+2), or hydrogen as +1 in metal hydrides NaH (-1)

Missing the peroxide (-1), oxygen difluoride (+2), and metal hydride (-1) oxidation state exceptions.

Open Fence-Post / Domain Trap Clinic

Try 1 Live Sample Question Under the 90-Second Stopwatch

Press W to open the 2-line dry-wipe scratchpad, select A–E, and lock in to reveal the Dual-View solution.

sub90 ESAT Stopwatch Emblemsub90 ESAT
ARCH-C-05: Oxidation State Assignment, Redox Disproportionation & Ionic Half-Equation Balancing (Sample)Chemistry
00:00.0
SUB-90 ZONE (<35S)
0.0s35s Sub-9090s ESAT Budget150s Classroom
Question 1 of 1ARCH-C-05 (6-Card Lesson)Format: Standard 5-Option
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Question 1 of 1 • 90s Target

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Chemistry•ARCH-C-05•Standard 5-Option
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